3/(x+1)-5/(x)=19/(x^2+x)

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Solution for 3/(x+1)-5/(x)=19/(x^2+x) equation:


D( x )

x = 0

x^2+x = 0

x+1 = 0

x = 0

x = 0

x^2+x = 0

x^2+x = 0

x^2+x = 0

DELTA = 1^2-(0*1*4)

DELTA = 1

DELTA > 0

x = (1^(1/2)-1)/(1*2) or x = (-1^(1/2)-1)/(1*2)

x = 0 or x = -1

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:0) U (0:+oo)

3/(x+1)-(5/x) = 19/(x^2+x) // - 19/(x^2+x)

3/(x+1)-(19/(x^2+x))-(5/x) = 0

3/(x+1)-19*(x^2+x)^-1-5*x^-1 = 0

3/(x+1)-19/(x^2+x)-5/x = 0

x^2+x = 0

x^2+x = 0

x*(x+1) = 0

x+1 = 0 // - 1

x = -1

x*(x+1) = 0

3/(x+1)-19/(x*(x+1))-5/x = 0

(3*x)/(x*(x+1))-19/(x*(x+1))+(-5*(x+1))/(x*(x+1)) = 0

3*x-5*(x+1)-19 = 0

3*x-5*x-19-5 = 0

-2*x-24 = 0

(-2*x-24)/(x*(x+1)) = 0

(-2*x-24)/(x*(x+1)) = 0 // * x*(x+1)

-2*x-24 = 0

-2*x-24 = 0 // + 24

-2*x = 24 // : -2

x = 24/(-2)

x = -12

x = -12

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